Have a great day Please upvote my answers , if it helped you1 2 3 π sin asin 4 5 6 − e cos acos exp ← 7 8 9 × g tan atan ln, • 0 E ∕ R rad deg log(a,b) ans;6 Answers6 Consider the function Differentiating gives , so the function attains its global maximum at Thus , and it is clear that the inequality is strict, so If you know Taylor expansion then We can get (Or you may take derivative to prove it) Then set We get
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Value of e^pi/2-Thus i i = (e iπ/2) i = e i2π/2 = e π/2 Thus i i is a real number!π 2 Ê Ë ÁÁ ÁÁ ÁÁ ˆ ¯ ˜˜ ˜˜ ˜˜ 41 Find the exact value of csc π 6 42 Find the exact value of sec π 6 43 Find the exact value of cot π 6 44 Find the exact value of cot π 4 45 Find the exact value of csc π 4 46 Find the exact value of sec π 2 47 Find the exact value of csc π 2 48 If the cosθ= − 5 13 and sinθ< 0
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The value of I = ∫ π / 2 5 π / 2 e t a n I = ∫ 0 2 π e s i n 2 x s i n x 1 dx , then Hard View solutionIf sin^2θcos^42θ=3/4, qe (0,π/2) then sum of all values of θ is(a) π/2(b) π(c) 3π/2(d) None of theseDownloads our APP for FREE Study Material ,Video Cla2 is the solution on π,2π), and u 3 satisfies satisfies the DE on 2π,∞) We impose u 1 (0) = 0,u0 (0) = 0 This will uniquely determine u 1 Compute u 1(π),u0 (π) and with these values solve the IVP u00 2u = F 0(2π −t), u (π) = u 1(π), u0 2 (π) = u0 1 (π) Now u 2 is uniquely determined, so we can solve the IVP for u 3 u00 3
Short answer 2 pi is approximately , with ten decimals Long answer The most exact answer is just what you wrote in the question 2pi Let me explain pi is a number that is irrational That means, there is an infinite number of dThe value of e is so on Just like pi (π), e is also an irrational number It is described basically under logarithm concepts 'e' is a mathematical constant, which is basically the base of the natural logarithm This is an important constant which is used in not only Mathematics but also in Physics2 e in x π x L x einxπx Lx e in y π y L y einyπy Ly, with n x and n y = 1,2,3, Show that this wavefunction is normalized 10 Using the same wavefunction, Ψ (x,y), given in exercise 9 show that the expectation value of p x vanishes 11 Calculate the expectation value of the x 2 operator for the first two states of the harmonic
The value of limx→1tanxπ4tanπx2 is e−2 e−1 e 1 limx→1tanxπ4tanπx21∞fromelimx→1tanxπ4−1tanπx2=elimx→1sinπx4− A Integers that are very close to values of , , , , , , } A Values of n for which e π2 Solution (i)ez = exeiy = 2eiπ3 ⇒ x = ln2y = π 3 2nπ, z = ln2 πi 3 2nπi (ii)e2z−1 = e2x−1e2iy = eiπ 2 ⇒ x = 1 2, y = π 4 nπ, z = 1 2 πi 4 nπi (iii) logz = iπ 2 ⇒ z = eπi 2 = i 8 Write the following complex numbers in standart form abi (i) e23iπ, (ii) e2iπ 4, (iii) log(−1i √ 3),
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E The number e, also known as Euler's number, is a mathematical constant approximately equal to 2718, and can be characterized in many ways It is the base of the natural logarithm It is the limit of (1 1/n)n as n approaches infinity, an expression that arises in the study of compound interest e π > π e Method 2 π to e(ln(π)) The natural logarithm is a monotonically increasing function This means we can take the natural log of two expressions and compare the size of the resulting values Thus we can compare ln(e π) = π ln(π e) = e ln(π) Our attack will be similar to method 1The PI function returns the value of π (pi) accurate to 15 digits The value of π represents a halfturn in radians and appears in many formulas relating to the circle The PI function takes no arguments = PI // returns
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The value of ∣∣∣∣a1a2a3a4a5a6a7a8a9∣∣∣∣ is where ar=cos 2r πi sin 2r π19 0 cos 5π cos 9π7i sin 9π7 2 ar=cos 2rπi sin 2rπ19=ei2rπ9=∣∣∣∣∣∣ei2π9ei4π9ei6π9Putting the value of ∫ 0 2 π e x c o s x d x in (1), we get I = e 2 π − 2 { 2 1 ( e 2 π − 1 ) } = e 2 π − e 2 π 1 = 1 Answer verified by TopprDiagnostic Value of Photofragment Anisotropy Measurements We applied this method to the e 1 Π u ( v = 0, J = 1,,9) levels of N 2 These levels predissociate by two different mechanisms to N\(2 P o \)N 4 S o and N\(2 D o \)N 4 S o and each dissociation mechanism
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The identity e^(iπ)1 = 0 is a well known equation that can be proven mathematically It is an identify that contains the most beautiful entities encountered in math, namely π, i, e, 0 and 1 #e^(varphii)=cos varphi isinvarphi# In the given example we get #e^(pi/2i)e^((2pi)/3i)=(cos(pi/2)isin(pi/2))(cos((2pi)/3)isin((2pi)/3))=# #=i(cos(pipi/3)isin(pipi/3))=# #=i(cos(pi/3)isin(pi/3))=# #=icos(pi/3)isin(pi/3)=# #i1/2sqrt(3)/2*i=1/2(1sqrt(3)/2)i#Hello Family !ये है कल की 3 videos !
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2 π Z π 0 f(x)cosnxdx = 2 π Z π 0 xcosnx dx If n = 0, then a0 = 2 π Z π 0 x dx = π, and if n ≥ 1, then integrating by parts, one finds that 2 π Z π 0 xcosnx dx = 2 π xsinnx n − 2 nπ Z π 0 sinnx dx = 2 n2π cosnx π 0 = 2 n2π (−1)n − 1 Hence an = 0 if n is even and an = − 4 n2π when n is odd, and hence f(x) ∼ π 2I lies on the y axis of the Argand Plane , which means that it's modulus is 1 and argument is π/2 So , it can be represented as So , log = iπ/2 log e = π/2 i(0434) = (0434)×(π/2)× i = (0434)(1570) i = (061) i So , logi = (061) i Hope this answer helps !!!Jaroor dekhe 😊👉 https//youtube/WsnJVnUjjkc👉 https//youtube/F8WfZ6ILM30👉 https//youtube
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